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(F)=F^2-36/25
We move all terms to the left:
(F)-(F^2-36/25)=0
We get rid of parentheses
-F^2+F+36/25=0
We multiply all the terms by the denominator
-F^2*25+F*25+36=0
Wy multiply elements
-25F^2+25F+36=0
a = -25; b = 25; c = +36;
Δ = b2-4ac
Δ = 252-4·(-25)·36
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-65}{2*-25}=\frac{-90}{-50} =1+4/5 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+65}{2*-25}=\frac{40}{-50} =-4/5 $
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